Top Back Link Checker Online Tools | Website Back Link Checking Tool

Best Free Online Back link Checker Tools Online Back link checker tool 

Being a blogger and webmaster, It's important to learn the basics of search engine optimization. We've discussed many things about SEO for newbies and also for pros. If you're known a bit to SEO then you might have heard about backlinks. We've also written several posts about backlinks which are how to increase backlinks, nofollow and dofollow links, get high PR backlinks and many more. Well, creating backlinks is just another thing which we should do regularly in order to good rank in SERP. But sometimes, we're interested to know that how much backlinks we've made till now. There are many ways for this to check the backlinks of our blog but in this post, I'm going to share some best backlink checker tools which will help you to analyze your backlinks easily.

1. Ahrefs

Ahrefs has the largest index of live backlinks which are updated after every 15 minutes, it's quite simple to use for any beginner yet it provide deep enough statistics that are needed and trusted by gurus, it provide stats such as, inbound and internal backlinks, anchor text cloud,  incoming links TLD chart etc. Ahrefs have paid plans starting from 79$ monthly to 499$ monthly and free version of Ahrefs can allow you to see up to 10 backlinks per request (you can see the exact number but details will only be shown of 10 first backlinks).

2. Majestic SEO

Majestic SEO is one of the oldest backlink checker tool, although it can be a little hard for any newbie to get hang of it metric showing interface but once you do you won't regret it, it can show 90 days accurate backlink history of any domain and some usual basic features such as anchor text cloud, backlink attribute chart. MajesticSEO plans starts from 49.99$ monthly to whopping 1599.96$ monthly, although free version won't allow you to see detailed reports but still there's a lot you can do with it.

3. Open Site Explorer

Open Site Explorer is owned by Moz (formally known as SEOMOZ ), it's one of the best new tool out there, it shows some of the newest metrics like domain authority and page authority, and the basic usual info as well, you can compare sites as well head to head. Open Site Explorer packages starts from 99$ per month to 599$ per month, and you can get free 30 days trial of its 99$ per month stand package without any commitment.

4. Backlink Watch

Backlink watch is a free backlink explorer which is powered by Ahrefs but the difference between it and ahrefs is that in backlinkwatch you can see every backlink linking to your domain without paying a dime although the report isn't as fancy as it's in Ahrefs but it's free and accurate.

5. Link Diagnosis

Link diagnosis is powered  by Iacquire, it's a free tool just like Backlinkwatch, there are several settings to play with before requesting report for your domain like you can change the engine, report type etc.

Automatic street Light system using microcontroller

Automatic Street Light Control System.(Sensor using LDR & Transistor BC 547.) Very Simple.

Briefing:

Her is our new simple Electrical/Electronics project about Automatic Street Light Control System. 

• it is a simple and powerful concept, which uses transistor (BC 547 NPN) as a switch to switch ON and OFF the street light system automatically.
• It automatically switches ON lights when the sunlight goes below the visible region of our eyes. (e.g in evening after Sunset). 
• it automatically switches OFF lights when Sunlight fall on it  ( i.e on LDR ) e.g in morning, by using a sensor called LDR (Light Dependent Resistor) which senses the light just like our eyes. 

Advantages:

• By using this Automatic system for street light controlling, we can reduce energy consumption because the manually operated street lights are not switched off properly even the sunlight comes and also not switched on earlier before sunset. 
• In sunny and rainy days, ON  and OFF time differ noticeably which is one of the major disadvantage of using timer circuits or manual operation for switching the street light system.

Enough....Now lets begin ( Step by Step)

Requirements

• LDR Light Dependent Resistor
• Take 2 transistors. (NPN transistor- BC547 or BC147 or BC548)
• Resistor- 1K, 330Ohm, 470 ohm
• Light emitting diode (LED) - Any color
• Connecting wires- Use single-core plastic-coated wire of 0.6mm diameter (the standard size)-You can use wire that is used for Computer Networking.
• Power supply-6V or 9V

Procedure

• Insert first transistor Q1-BC547 (NPN) on breadboard (or general PCB) as shown in the circuit diagram 1.
• Connect another transistor Q2- BC547 (NPN) on breadboard as in step 1.
• Connect  wires across emitter pin of both transistors and –ve terminal of battery (lowest/ bottom row of breadboard.)
• Connect  a wire across Collector pin of transistor Q1 and Base pin of transistor Q2.
• Connect a resistor 1K across positive terminal of battery (topmost row of breadboard) and Collector pin of transistor Q1.
• Connect  Light Dependent Resistor (LDR) across positive terminal of battery (topmost row of breadboard) and base terminal of transistor Q1.
• insert a resistor- 330 Ohm across base pin of transistor Q1 and negative terminal of battery (lowest bottom row of breadboard).
• Connect a resistor 330R across positive terminal of battery (topmost row of breadboard) and anode terminal of LED (Light emitting diode) & Connect the cathode terminal of LED to Collector pin of transistor Q2.

The simple circuit is ready for testing now. Connect 6V battery terminals to the circuit as show in figand see the output. As you block light falling on Light dependent resistor (LDR), the LED glows.

LED GLOWS EVEN IN LESS DARKNESS. Use torch light or Lighter if the LED glows in less darkness. in addition, you can try to adjust the sensitivity of this circuit by using a variable resistor in place of R1-300Ohm. Try this circuit with other resistances as well, (e.g, 1KΩ, 10KΩ and 100KΩ, etc)

Circuit Diagram 1.Automatic Street Light Control System.(Sensor using LDR & Transistor BC 547.) Very Simple.  We have tried this one in this tutorial bu you can also try the second one

Circuit Diagram 2 .Automatic Street Light Control System.(Sensor using LDR & Transistor BC 547.) Very Simple.

                                               

You can see now that we have blocked light falling on Light dependent resistor (LDR), so the LED glows ( LED = ON)            

Astrologer In Jaipur Astrologer In Jaipur

Capacitor In Series Calculation formula

Formula & Equations for This Calculator

Finding Total Series Capacitance (C T ) when C 1 and C 2 Given;
1/C T = 1/C 1 + 1/C 2 C T = C 1 ||C 2
C T = C 1 x C 2 / (C 1 + C 2 )
Finding C 1 when C T and C 2 Given;
C 1 = C 2 × C T / (C 2 – C T )
Finding C 2 when C T and C 1 Given;
C 2 = C 1 × R T / (C 1 – C T )

Maths problem on Mixtures and easy solutions

Mixtures questions and its solutions

This is the extension of Averages which we have discussed earlier.

Formulae and shortcuts used to solve the following problems are discussed in the previous post.

Solved Problems
1. Let the cost of 2 quantities of rice be Rs.15 and Rs.19 per kg. Find the ratio of mixture which cost Rs.18 per kg?
Soln.:
          Method1:
          Let the quantity of rice of quality A (Rs.15/kg) be 'x'
          Let the quantity of rice of quality B (Rs.19/kg) be 'y'
          As per the problem, 15x+19y = 18(x+y)
          y = 3x => x/y = 1/3
          Therefore, the ratio of quantities mixed to make the quality of Rs.18 is 1:3.

          Method2: Using shortcut,
         
              Therefore, ratio is 1:3
 
2. Let the cost of 2 quantities of rice be Rs.15 (quality A) and Rs.19 (quality B) per kg. Find the quantity of rice of quality A that has to be mixed with 27kg of quality B to make the cost of rice as Rs.18?
Soln.:
          Method1:
          Let the quantity of rice of quality A (Rs.15/kg) be 'x'
          Let the quantity of rice of quality B (Rs.19/kg) be 'y'
          As per the problem, 15x+19y = 18(x+y)
          y = 3x => x/y = 1/3
          Therefore, the ratio of quantities mixed to make the quality of Rs.18 is 1:3.
          => 3 parts of quality B is to be mixed with 1 part of quality A 
          => 27kg of quality B is to be mixed with 9kg of quality A.
          Ans: 9kgs

          Method2: Using shortcut,
         
              Therefore, ratio is 1:3
               => 3 parts of quality B is to be mixed with 1 part of quality A 
               => 27kg of quality B is to be mixed with 9kg of quality A.
               Ans: 9kgs

3. Let the cost of 2 quantities of rice be Rs.15 and Rs.19 per kg. These 2 qualities of rice are mixed and sold at Rs.27 per kg of profit 50%. Find the ratio in which 2 qualities of rice mixed?
Soln.:
          Method1:
          Let the quantity of rice of quality A (Rs.15/kg) be 'x'
          Let the quantity of rice of quality B (Rs.19/kg) be 'y'
          Given Selling price, SP = 27 and the profit % is 50%
          We know that the profit%, p% = (SP-CP)/CP * 100
          => 50/100 = (27 - CP)/CP
          => CP = 18
          As per the problem, 15x+19y = 18(x+y)
          y = 3x => x/y = 1/3
          Therefore, the ratio of quantities mixed to make the quality of Rs.18 is 1:3.

          Method2: Using shortcut,
          Given Selling price, SP = 27 and the profit % is 50%
          We know that the profit%, p% = (SP-CP)/CP * 100
          => 50/100 = (27 - CP)/CP
          => CP = 18
         
              Therefore, the ratio of quantities mixed to make the quality of Rs.18 is 1:3.

4. A man purchased TV and Washing machine for Rs.30000. He sold the TV at 30% profit and washing machine at 60% profit. He makes overall profit of 50%. Then find for how much did he purchased TV and washing machine?
Soln:
          Method1:
          Let the cost price of TV be 'x'
          Let the cost price of washing machine be 'y'
          As per the problem,
          x + y = 30000 ------> Eq. 1
          SP of TV = 1.3x
          SP of washing machine = 1.6y
          1.3x + 1.6y = 30000 * 1.5
          1.3x + 1.6y = 45000 --------> Eq. 2
          On solving equations 1 and 2, x = 10000 and y = 20000
          Therefore, cost price of TV and washing machine are Rs.10000 and Rs.20000 respectively.

          Method2: Using shortcut,

         
              Therefore, ratio is 1:2. 3 parts is equivalent to 30000
              => Cost of TV is 10000 (1 part) and Cost of washing machine is 20000 (2 parts)